Answer:
school building, so the fourth side does not need Fencing. As shown below, one of the sides has length J.‘ (in meters}. Side along school building E (a) Find a function that gives the area A (I) of the playground {in square meters) in
terms or'x. 2 24(15): 320; - 2.x (b) What side length I gives the maximum area that the playground can have? Side length x : [1] meters (c) What is the maximum area that the playground can have? Maximum area: I: square meters
Step-by-step explanation:
Answer:
-60
Step-by-step explanation:
Distribute
6 x -3 = -18
6 x -7 = -42
-18 - 42 = -60
If my answer is right, please give it the brainliest.
Answer:
The height of the another cylinder 'h' = 7
Step-by-step explanation:
<u>Explanation</u>:-
<u>Step 1:-</u>
Surface area of the cylinder = 2пrh + 2пr^2
Given radius of first cylinder is 20cm
given height of the first cylinder is 2 cm
The surface area of first cylinder is = 2пrh + 2пr^2
= 2п(20)(2)+2п(2)^2
= 4п(20+2)
The surface area of first cylinder is 88п
<u>Step 2</u>:
given data The surface area of first cylinder is 88п is same as second cylinder also
<u>Find the height of the second cylinder</u>
Given Radius of the second cylinder r = 4
Surface area of the cylinder = 2пrh + 2пr^2 = 88п
2п(4)h+2п(4)^2 =88п
on simplification we get
2п (4h+16) = 88п
after cancellation '2п' value and on simplification, we get
4h+16 = 44
4h = 44-16
4h = 28
h=7
Therefore the height of the another cylinder is 'h' =7
(2x+1)(x+5) is the answer.