If the amount she saved was $6 for 20%, then the formula for finding savings would be cost*percentage.
But if you want to find the original cost, then you play with the current formula until you get this. $6/20%. Have a good one :)
It's sometimes true.
One example is the least common multiple of 2 and 3 is 6, which is their product.
But the product isn't always the answer because (example 2:) the least common multiple of 6 and 10 is 30 because 6*5=30 and 3*10=30, however 6*10 is 60.
Ergo, it is only sometimes true.
Answer: There were 40 euros in the drawer at the beginning.
Step-by-step explanation:
When we subtract 6 from 16, we get 10 more ice-creams were sold.
Similarly, we subtract 70 from 120, we get 50 euros was the total selling price of 10 ice-creams.
i.e. Selling price of 1 ice-cream = (50)÷10 =5 euros
Selling price of 6 ice-creams = 6 x 5 = 30 euros
Money in the drawer at the beginning = 70-30 = 40 euros
Hence, there were 40 euros in the drawer at the beginning.
Answer:
Step-by-step explanation:
We need to sum the following two expressions:
expanding the polynomial in the numerator:
This is the most simplified form we can get: