By definition of conditional probability,
Similarly,
Here you can find x by solving 8x=-8 so x=-1. Then plug it in and you get 0
Answer:
Option (D)
Step-by-step explanation:
Given polynomial is,
2x³ - 3x² - 3x + 2
If (x - 2) is the factor of the given polynomial,
By synthetic division we can get the other factor.
2 | 2 -3 -3 2
<u> 4 2 -2 </u>
2 1 -1 0
Therefore, other factor of the given polynomial is (2x² + x - 1)
Now (2x² + x - 1) = 2x² + 2x - x - 1
= 2x(x + 1) -1(x + 1)
= (2x - 1)(x + 1)
Therefore, factors of the given polynomial other than (x - 2) are (2x - 1) and (x + 1)
Option (D) will be the answer.
Start by getting one of the equations in terms of one variable, in this case lets put the first equation in terms of y
2x+y=3 ---> y=3-2x
now we plug that into the second equation
5x-2y=12 ---> 5x-2(3-2x)=12
we can then multiply and simplify
5x-2(3-2x)=12 ---> 5x-6+4x=12 ---> 9x-6=12 ---> 9x=18 ---> x=2
we can now plug x=2 into an equation to solve for y
2(2)+y=3 ---> 4+y=3 ---> y=-1
