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2 years ago

3(2x) + 3(-1) = -21 6x - 3 = -21 What property is being used ?

Mathematics

1 answer:

kaheart [24]2 years ago

4 0

Distributive property, since 3(2x) you distribute and get 6x

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What's 107 divided by 97,156

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It is 0.00110132 that should be it.

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2 years ago

The square root of 30 times the square root of 3

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The answer is 9.48. also I rounded

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The power P produced by a wind turbine is directly proportional to the cube of the wind speed S. A wind speed of 37 miles per ho

vfiekz [6]

Answer:the output for a wind speed of 40 miles per hour is 810.8 kilowatts.

Step-by-step explanation:

The power P produced by a wind turbine is directly proportional to the cube of the wind speed S. This means that

P is directly proportional to S

Introducing a constant of proportionality, k, it becomes

P = kS

A wind speed of 37 miles per hour produces a power output of 750 kilowatts. This means that

750 = k × 37

k = 750/37 = 20.27

The expression becomes

P = 20.27S

Therefore, the output for a wind speed of 40 miles per hour would be

P = 20.27 × 40

P = 810.8

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2 years ago

Danny bought 5 Pes to $0.30 each six pencils at $0.25 since in The Notebook for $3 and the tax is $8 how much did he pay will ma

Paha777 [63]

The answer is 14. This is because 0.30 multiplied by 5 is 1.5. Then 6 multiplied by 0.25 is 1.5 as well. Adding these two together is 3. 3 plus 3 for the notebook is 6. Than 6 plus 8 dollar tax is 14 dollars.

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2 years ago

If 2.5 mol of dust particles were laid end to end along the equator, how many times would they encircle the planet? The circumfe

Natalka [10]

Answer:

They encircle the planet $3.76\times 10^{11}$ times.

Step-by-step explanation:

Consider the provided information.

We have 2.5 mole of dust particles and the Avogadro's number is $6.022\times 10^{23}$

Thus, the number of dust particles is:

$2.5\times 6.022\times 10^{23}=15.055\times 10^{23}$

Diameter of a dust particles is 10μm and the circumference of earth is 40,076 km.

Convert the measurement in meters.

Diameter: $10\mu m\times \frac{10^{-6}m}{\mu m} =10^{-5}m$

If we line up the particles the distance they could cover is:

$15.055\times 10^{23}\times 10^{-5}=15.055\times 10^{18}=1.5055\times 10^{19}$

Circumference in meters:

$40,076km\times \frac{1000m}{1km}=40,076,000 m$

Therefore,

$\frac{1.5055\times 10^{19}}{40,076,000} = 3.76\times 10^{11}$

Hence, they encircle the planet $3.76\times 10^{11}$ times.

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2 years ago