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2 years ago

7

I don’t know pls help me

2 answers:

Veronika [31]2 years ago

8 0

da ans 2 yo previous n dis ques

maw [93]2 years ago

4 0

Answer:

Step-by-step explanation:

Tykrkeek

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Can you divide 25 into 4 equal groups? Explain why or why not.

alexira [117]

Answer:

No, not really.

dividing 25 into 4 equal groups, equals 6.25.

So no, you can not divide 25 into 4 equal group.

If if was 25 into 5 equal groups, then yes.

Hope this helps!!!

Please mark brainliest, if this helps. :)

Step-by-step explanation:

8 0

2 years ago

If a+b=5 and a-b=4 then b^2-a^2 =

Anna007 [38]

Answer:

$a + b = 5 \\ a \: = 5 - b \\ a - b = 4 \\ 5 - b - b = 4 \\ 5 - 2b = 4 \\ 5 - 4 = 2b \\ 1 = 2b \\ \frac{1}{2} = \frac{2b}{2} \\0.5 = b \\ b = 0.5 \\ a = 5 - b \\ = 5 - 0.5 \\ = 4.5 \\ {a \: }^{2} - {b}^{2} = ( {4.5}^{2}) - ( {0.5}^{2} ) \\ = 20.25 - 0.25 \\ = 20 \\ {a}^{2} - {b}^{2} = 20$

Step-by-step explanation:

HOPE THAT THIS IS HELPFUL.

HAVE A GREAT DAY.

5 0

2 years ago

The man paid $21 for a book bag that was taxed 20%. What was the original price of the bag?

Vlad1618 [11]

Answer:

15

Step-by-step explanation:

7 0

2 years ago

Read 2 more answers

Find an equation of the line that has the given slope and contains the given point. m=7/3 (1,6)

iris [78.8K]

The point-slope form:

$y-y_1=m(x-x_1)$

We have the point (1, 6) and the slope m = 7/3. Substitute:

$y-6=\dfrac{7}{3}(x-1)$ <em>use distributive property</em>

$y-6=\dfrac{7}{3}x-\dfrac{7}{3}$ <em>add 6 to both sides</em>

$y=\dfrac{7}{3}x+\dfrac{11}{3}$ <em>multiply both sides by 3</em>

$3y=7x+11$ <em>subtract 7x from both sides</em>

$-7x+3y=11$ <em>change the signs</em>

$7x-3y=-11$

Answer:

point-slope form: $y-6=\dfrac{7}{3}(x-1)$

slope-intercept form: $y=\dfrac{7}{3}x+\dfrac{11}{3}$

standard form: $7x-3y=-11$

5 0

2 years ago

What value(s) of x will make each equation below true

Dahasolnce [82]

We need to solve for x. Let's try problem b:

$2x-6=3x+1-x-7$

Let us first combine line terms. 3x and -x as well as 1 and -7 can be combined. Let's do that:

$2x-6=2x-6$

Since this is true, your answer would be:

All real numbers

------------------------------------------------------------------

Let's solve for problem c:

$3x+1=43$

Let's isolate x, so subtract 1 from both sides:

$3x=42$

Since x can't have a coefficient, divide both sides by 3:

$\frac{3x}{3}=\frac{42}{3}$

$x=14$

So, only the value of 14 would make this equation true.

------------------------------------------------------------------

Let's try problem d:

$4x-1=4x+7$

Let's get our whole numbers on the right side. Add 1 to both sides:

$4x=4x+8$

Subtract 4x from the right side on both sides:

$0=8$

Since this is not true, your answer would be:

No solution

7 0

3 years ago