<span>For a system of equations to have infinitely many solutions, the equations have to be lineary dependent, (i.e. one of the equations is a multiple of the other equation). For the given equation to have infinitely many solutions, the second equation have to be a multiple of the first equation.
The first equation can be rewritten as y - 2x = -5
The second equation is the first equation multiplied by 2, i.e. 2(y - 2x= -5) = 2y - 4x = -10
Therefore, the correct answer is -10 (option a).</span>
Answer:
10
Step-by-step explanation:
15 = 1/2 * b * 3
15 * 2 = 3 * b
b = 30/3
b = 10 m
Answer:
Step-by-step explanation:
27^1/3
27 is cube root of 3
so it can also be written as (3)^3
∴ {(3)^3}^1/3
3 and 3 will get cancelled
so it will be 3^1
= 3
The answer is C: first add 2 both sides then divide both sides by -5.
Quadratic formula: (-b +/- sqrt(b^2 - 4ac)) / 2a
a = 10
b = -1
c = 9
1 +/- sqrt((-1)^2 - 4(10)(9)) / 2(10)
1 +/- sqrt(1 - 360) / 20
x = 1 +/- sqrt(359i) / 20
Hope this helps!
