Answer:
70° is the answer hope it helps
30°+90°+ 3y= 180°
120°+3y= 180°
3y= 180°-120°
y= 60°/3
y= 20°
Now
y°+90°+x°= 180°
20°+90°+x= 180°
x= 180°-110°
x= 70°
Answer:
There is no point of the form (-1, y) on the curve where the tangent is horizontal
Step-by-step explanation:
Notice that when x = - 1. then dy/dx becomes:
dy/dx= (y+2) / (2y+1)
therefore, to request that the tangent is horizontal we ask for the y values that make dy/dx equal to ZERO:
0 = ( y + 2) / (2 y + 1)
And we obtain y = -2 as the answer.
But if we try the point (-1, -2) in the original equation, we find that it DOESN'T belong to the curve because it doesn't satisfy the equation as shown below:
(-1)^2 + (-2)^2 - (-1)*(-2) - 5 = 1 + 4 + 2 - 5 = 2 (instead of zero)
Then, we conclude that there is no horizontal tangent to the curve for x = -1.
u is at (1,-2)
V is at (-6,-6)
using distance formula it is about 8.06 long
so Answer is C
This is the answer with the correct work.
sin α = opposite leg/ hypotenuse
For ΔABC,
sin A = |BC|/|AB|
sin A = 12/37
