As with simple linear regression, we desire the residuals to:
- Have constant variance.
- Have a mean close to 0.
<h3>What is a simple linear regression?</h3>
It should be noted that a simple linear regression simply means a model that describes the relationship between a dependent variable and an independent variable.
In this case, as with simple linear regression, we desire the residuals to have constant variance and have a mean close to 0.
Learn more about regression on:
brainly.com/question/25987747
Answer:
{8 cm, 15 cm, 17 cm}
Step-by-step explanation:
we know that
The length sides of a right triangle must satisfy the Pythagoras Theorem
so
where
c is the greater side (the hypotenuse)
a and b are the legs (perpendicular sides)
<u><em>Verify each case</em></u>
case 1) we have
{5 cm, 15 cm, 18 cm}
substitute in the formula
----> is not true
therefore
Sean cannot make a right triangle with this set of lengths
case 2) we have
{6 cm, 12 cm, 16 cm}
substitute in the formula
----> is not true
therefore
Sean cannot make a right triangle with this set of lengths
case 3) we have
{5 cm, 13 cm, 15 cm}
substitute in the formula
----> is not true
therefore
Sean cannot make a right triangle with this set of lengths
case 4) we have
{8 cm, 15 cm, 17 cm}
substitute in the formula
----> is true
therefore
Sean can make a right triangle with this set of lengths
It might either be a right triangle or a cute triangle
Answer:
.
Step-by-step explanation:
We have been given that Mrs. Chen's students are making and decorating gift boxes for a nursing home. The boxes are 7 inches wide, 7 inches long, and 7 inches high. We are asked to find the amount of cardboard that is needed for each box.
We will use surface area of cuboid formula to solve our given problem.
, where,
l = Length,
w = Width,
h = Height
Therefore, Mrs Chen needs 84 square inches of cardboard.
Answer:
Jacqueline runs at 6.25 minutes per mile
Step-by-step explanation:
Here we have that the total training time for Jacqueline = 54 minutes
The time for which Jacqueline swims = 30 minutes
Therefore, the time in which Jacqueline runs = 54 min. - 30 min. = 20 minutes
Therefore the equation for Jacqueline's speed = Distance/Time we have
Jacqueline's pace = 3.2 miles/20 minutes = 0.16 miles/minute
Therefore Jacqueline's pace = 0.16 miles/minute
The equation for Jacqueline's pace in miles/minute is presented as follows
Jacqueline's pace in miles/minute = Time of running/Distance
Jacqueline's pace in miles/minute = 1/0.16 miles/minute = 6.25 minutes/mile.