The volume and surface area of the pyramid will be 392 / 3 cubic units and 189 square units. Then the correct option is A.
The complete question is attached below.
<h3>What is the volume and surface area of the pyramid? </h3>
Suppose the base of the pyramid has length = L units, width = W units, slant height = K units, and the height of the pyramid is of H units.
Then the volume of the pyramid will be
V = (L × B × H) / 3
The surface area of the pyramid will be
SA = 2(1/2 × B × K) + 2(1/2 × L × K) + (L × B)
Then the volume will be
V = (7 × 7 × 8) / 3
V = 392/3 cubic units
Then the surface area will be
SA = 2(1/2 × 7 × 10) + 2(1/2 × 7 × 10) + (7 × 7)
SA = 189 square units
Then the correct option is A.
More about the volume and surface area of the pyramid link is given below.
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Outcome
Hope this helps :)
Answer:
d) 87
Step-by-step explanation:
to solve this lets set up the equation
then we multiply 4 on both sides
253+x=340
and subtract 253 on both sides
x=87
to double check take the averages
(87+85+70+98)/4=85
Answer:
The maximum value of the table t(x) has a greater maximum value that the graph g(x)
Step-by-step explanation:
The table shows t(x) has two (2) x-intercepts: t(-3) = t(5) = 0. The graph shows g(x) has two (2) x-intercepts: g(1) = g(5) = 0. Neither function has fewer x-intercepts than the other.
The table shows the y-intercept of t(x) to be t(0) = 3. The graph shows the y-intercept of g(x) to be g(0) = -1. The y-intercepts are not the same, and that of t(x) is greater than that of g(x).
The table shows the maximum value of t(x) to be t(1) = 4. The graph shows the maximum value of g(x) to be g(3) = 2. Thus ...
the maximum value of t(x) is greater than the maximum value of g(x)