The population Pa of insect A after t years is given by the equation
Pa = 1.3(1-0.038)^t
while the population Pb of insect B after t years is
Pb = 2.1(1-0.046)^t
We equate the above expressions to find the number of years t it will take the two populations to be equal:
Pa = Pb
1.3(1-0.038)^t = 2.1(1-0.046)^t
1.3(0.962)^t = 2.1(0.954)^t
These are the equations that can be used to determine how long it will be before the populations of the two species are equal.
We can now solve for t:
(0.962)^t / (0.954)^t = 2.1/1.3
(0.962/0.954)^t = 2.1/1.3
After taking the log of both sides of our equation, number of years t is
t = log (2.1/1.3) / log (0.962/0.954)
t = 57 years
Therefore, it will take 57 years for the population of insect A to equal the population of insect B.
Answer:
(0,5)
Step-by-step explanation:
I'm really not sure but I'm pretty positive that this is the answer if not than my bad
So set up an equation!
7* n/4 > 7
So trying to get the variable alone...
n/4 > (7/7) aka 1
n> 1*4
n> 4
Try it out!
7* 6/4 = 42/4 = 21/2= 10 and 1/2
It is greater than 7
Let x = Darlene's dog's weightlet y = Leah's dog's weight x = 5yx + y = 84 so, 5y + y = 84, which means 6y = 84 so, y = 84/6 = 14x = 5(14) = 70 Darlene's dog = 70 lbs, Leah's dog = 14 lbs.<span> </span>