Answer:
D. 274
Step-by-step explanation:
divide 1787 by 6.5 yds to get the answer, 274.
Answer:
The space left inside the cyclinder =36π(h - 24)
step-by-step explanation:
Radius of sphere = 6cm
Diameter of cylinder = 12cm
Radius of cylinder = d / 2 = 12 /2 = 6cm
Formula for volume of a sphere = 4/3 πr³
Formula for volume of volume of a cylinder = πr²h
r = radius
h = height
The volume of one sphere = 4/3πr³
Volume of 4 spheres = 4 * 4/3πr³ = 12/3 πr³ = 4πr³
But radius of the sphere = 6cm
Volume of the sphere = 4 * π * 6³
Volume of the sphere = 864π
Let the space left in the cylinder = x
The space left in the cylinder (x) = volume of the cylinder - total volume of the spheres
x = πr²h - 4πr³
Note : both radius = 6cm and we can just substitue it
x = πr² (h - 4r)
x = π*6² (h - 4*6)
x = 36π (h - 24)
The space left inside the cylinder = 36π(h - 24) since we don't know the value of the height of the cylinder.
Its all up to you and how hard you are willing to work to get that may credits in one semester. But you could do it. Hope that helped!
7k + 4 is the simplified version
Answer: A) .1587
Step-by-step explanation:
Given : The amount of soda a dispensing machine pours into a 12-ounce can of soda follows a normal distribution with a mean of 12.30 ounces and a standard deviation of 0.20 ounce.
i.e. 
and 
Let x denotes the amount of soda in any can.
Every can that has more than 12.50 ounces of soda poured into it must go through a special cleaning process before it can be sold.
Then, the probability that a randomly selected can will need to go through the mentioned process = probability that a randomly selected can has more than 12.50 ounces of soda poured into it =
![P(x>12.50)=1-P(x\leq12.50)\\\\=1-P(\dfrac{x-\mu}{\sigma}\leq\dfrac{12.50-12.30}{0.20})\\\\=1-P(z\leq1)\ \ [\because z=\dfrac{x-\mu}{\sigma}]\\\\=1-0.8413\ \ \ [\text{By z-table}]\\\\=0.1587](https://tex.z-dn.net/?f=P%28x%3E12.50%29%3D1-P%28x%5Cleq12.50%29%5C%5C%5C%5C%3D1-P%28%5Cdfrac%7Bx-%5Cmu%7D%7B%5Csigma%7D%5Cleq%5Cdfrac%7B12.50-12.30%7D%7B0.20%7D%29%5C%5C%5C%5C%3D1-P%28z%5Cleq1%29%5C%20%5C%20%5B%5Cbecause%20z%3D%5Cdfrac%7Bx-%5Cmu%7D%7B%5Csigma%7D%5D%5C%5C%5C%5C%3D1-0.8413%5C%20%5C%20%5C%20%5B%5Ctext%7BBy%20z-table%7D%5D%5C%5C%5C%5C%3D0.1587)
Hence, the required probability= A) 0.1587
