Explanation:
Given:
v₀ = 22 m/s
v = 0 m/s
t = 17.32 s
Find: a
v = at + v₀
(0 m/s) = a (17.32 s) + (22 m/s)
a = -1.270 m/s²
Round as needed.
Answer:
v = (10 i ^ + 0j ^) m / s, a = (0i ^ - 9.8 j ^) m / s²
Explanation:
This is a missile throwing exercise.
On the x axis there is no acceleration so the velocity on the x axis is constant
v₀ₓ = 10 m / s
On the y-axis velocity is affected by the acceleration of gravity, let's use the equation
v_y = - g t
at the highest point of the trajectory the vertical speed must be zero
v_y = 0
therefore the velocity of the body is
v = (10 i ^ + 0j ^) m / s
the acceleration is
a = (0 i ^ - g j⁾
a = (0i ^ - 9.8 j ^) m / s²
Answer:
New_momentum = 750 [kg.m/s]
Explanation:
Momentum is defined as
M = mass* velocity
Original momentum
M_old = 100 Kg * 5 m/s = 500 [kg.m/s]
If the car pulls over and picks up two people. The mass of the car is now 150 kg, but the velocity stays the same.
New momentum
M_new = 150 Kg * 5 m/s = 750 [kg.m/s]