Answer:
0.872<em>m/s</em>
Explanation:
Tangential velocity is given by the formula,
In the question given,
radius= 25meters
time= 180secs
pie= 3.14
number of laps= 1
The magnitude of tangential velocity equals;
<em>v </em>= 157<em>m</em>/180<em>secs</em>
Therefore, the magnitude of the tangential velocity
=0.872<em>m/secs</em>
Refer to the diagram shown below.
Still-water speed = 9.5 m/s
River speed = 3.75 m/s down stream.
The velocity of the swimmer relative to the bank is the vector sum of his still-water speed and the speed of the river.
The velocity relative to the bank is
V = √(9.5² + 3.75²) = 10.21 m/s
The downstream angle is
θ = tan⁻¹ 3.75/9.5 = 21.5°
Answer: 10.2 m/s at 21.5° downstream.
Answer:
5.7141 m
Explanation:
Here the potential and kinetic energy will balance each other
This is the initial velocity of the system and the final velocity is 0
t = Time taken = 0.04 seconds
F = Force = 18000 N
a = Acceleration
g = Acceleration due to gravity = 9.81 m/s²
Equation of motion
From Newton's second law
Squarring both sides
The height from which the student fell is 5.7141 m
Forces of gravity and magnets.
Answer:
Explanation:
A ball is thrown in forward direction by a person who is riding on the roof of the moving train.
-->If you neglected the air drag and relative to the ground, then the velocity of the ball is equal to the sum of the velocities of ball and the train.
-->Hence, the ball is moving faster.
-(b) Relative to the freight car, the ball moves at the same speed irrespective of train
