Answer:
Part A) For the number of hours less than 5 hours it make more sense to rent a scooter from Rosie's
Part B) For the number of hours greater than 5 hours it make more sense to rent a scooter from Sam's
Part C) Yes, for the number of hours equal to 5 the cost of Sam'scooters is equal to the cost of Rosie's scooters
Part D) The cost is $90
Step-by-step explanation:
Let
x-------> the number of hours (independent variable)
y-----> the total cost of rent scooters (dependent variable)
we know that
Sam's scooters
Rosie's scooters
using a graphing tool
see the attached figure
A. when does it make more sense to rent a scooter from Rosie's? How do you know?
For the number of hours less than 5 hours it make more sense to rent a scooter from Rosie's (see the attached figure) because the cost in less than Sam' scooters
B. when does it make more sense to rent a scooter from Sam's? How do you know?
For the number of hours greater than 5 hours it make more sense to rent a scooter from Sam's (see the attached figure) because the cost in less than Rosie' scooters
C. Is there ever a time where it wouldn't matter which store to choose?
Yes, for the number of hours equal to 5 the cost of Sam'scooters is equal to the cost of Rosie's scooters. The cost is $70 (see the graph)
D. If you were renting a scooter from Rosie's, how much would you pay if you were planning on renting for 7 hours?
Rosie's scooters
For x=7 hours
substitute
The cost is $90
Answer:
She read 76 pages each day
Step-by-step explanation:
380/5=76
Answer:
a 2
b -1
Step-by-step explanation:
Answer:
d. 9.95h + 5 < 125
Step-by-step explanation:
i hope this helps :)
Answer:
f(x) = (x+2) (x+2)^3 (x-1) (x-6)
Step-by-step explanation:
The first zero, -2, corresponds to the factor x+2 of the polynomial.
Given that this zero, -2, has multiplicity 3, (x+2)^3 represent the first three factors of the polynomial.
The next factor stems from the zero 1: (x-1).
The next 6 factors stem from the zero 6: (x-6).
Writing the polynomial in factored form, we get:
f(x) = (x+2) (x+2)^3 (x-1) (x-6)