Answer:
Segment B C and Segment P N
Step-by-step explanation:
we know that
Line segments are congruent if they have the same length
In this problem
we have
Segment L.M ≅ Segment F.A
Segment M.N ≅ Segment A.B
Segment P.N ≅ Segment B.C
Segment P.J ≅ Segment C.D
Segment J.K ≅ Segment E.D
Segment K.K ≅ Segment F.E
therefore
The answer is
Segment B C and Segment P N
Answer:
$25.55
Step-by-step explanation:
7.30*2.50=18.25
7.30+18.25=25.55
First write both vectors in terms of their horizontal and vertical components.
G = (40.3 m)(cos(-35.0º) x + sin(-35.0º) y)
G = (33.0 x - 23.1 y) m
(where x and y are the unit vectors that point in the positive horizontal and vertical directions, respectively)
H = (63.3 m)(cos 270º x + sin 270º y)
H = (-63.3 y) m
Then the vector sum is
G + H = (33.0 x - 86.4 y) m
which has a magnitude of
|| G + H || = √[33.0^2 + (-86.4)^2] = 92.5 m
Y=-1.5x + 8
hope this helps :) (please mark brainliest!)
Answer:
The phase difference between yA and yB is
Step-by-step explanation:
Given harmonic modeled as :
yA = 8 sin(2t - ) And
yB = 8 sin(2t - )
The function as written as :
y = a sin(ωt - Ф) where Ф is phase difference
So , phase difference between yA and yB = ( Ф_1 - Ф_2 )
Or phase difference between yA and yB = ( - + )
Or, phase difference between yA and yB =
I.e phase difference between yA and yB =
Hence The phase difference between yA and yB is Answer