we know that
the volume of a solid oblique pyramid is equal to
where
B is the area of the base
h is the height of the pyramid
in this problem we have that
B is a square
where
<u>
</u>
so
substitute in the formula of volume
![V=\frac{1}{3}*x^{2}*(x+2)\\ \\V=\frac{1}{3}*[x^{3} +2x^{2}]\ cm^{3}](https://tex.z-dn.net/?f=V%3D%5Cfrac%7B1%7D%7B3%7D%2Ax%5E%7B2%7D%2A%28x%2B2%29%5C%5C%20%5C%5CV%3D%5Cfrac%7B1%7D%7B3%7D%2A%5Bx%5E%7B3%7D%20%2B2x%5E%7B2%7D%5D%5C%20cm%5E%7B3%7D)
therefore
<u>the answer is</u>
![V=\frac{1}{3}*[x^{3} +2x^{2}]\ cm^{3}](https://tex.z-dn.net/?f=V%3D%5Cfrac%7B1%7D%7B3%7D%2A%5Bx%5E%7B3%7D%20%2B2x%5E%7B2%7D%5D%5C%20cm%5E%7B3%7D)
Answer:
Step-by-step explanation:
Since the distance travelled on 1 gallon of fuel is normally distributed, we would apply the formula for normal distribution which is expressed as
z = (x - µ)/σ
Where
x = the distance travelled.
µ = mean distance
σ = standard deviation
From the information given,
µ = 50 miles
σ = 8 miles
A) P(x > 53) = 1 - P(x ≤ 53)
For x = 53,
z = (53 - 50)/8 = 0.38
Looking at the normal distribution table, the probability value corresponding to the z score is 0.648
B) P(x < 42)
For x = 42
z = (42 - 50)/8 = - 1
Looking at the normal distribution table, the probability value corresponding to the z score is 0.1587
C) P(44 ≤ x ≤ 53)
For x = 44
z = (44 - 50)/8 = - 0.75
Looking at the normal distribution table, the probability value corresponding to the z score is 0.2266
For x = 55,
z = (55 - 50)/8 = 0.63
Looking at the normal distribution table, the probability value corresponding to the z score is 0.7357
Therefore,
P(44 ≤ x ≤ 53) = 0.7357 - 0.2266 = 0.5091
We know that the building must form a right angle with the ground, so the triangle formed by the ladder, the wall, and the distance between the base of the ladder and the wall is a right triangle. We can use the Pythagorean theorem to find the distance the ladder is from the building.
a^2 + b^2 = c^2
We know that the ladder is the hypotenuse because it is opposite the right angle.
a^2 + b^2 = 20^2
Substitute the length of the other side and solve.
a^2 + 17^2 = 20^2
a^2 + 289 = 400
a^2 = 111
The distance from the wall to the bottom of the ladder is the square root of 111 or approximately 10.5357 feet
