Answer:
D.) All of the above
Explanation:
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Answer:
1.2 × 10⁴ cal
Explanation:
Given data
- Initial temperature: 80 °C
We can calculate the heat released by the water () when it cools using the following expression.
where
c is the specific heat capacity of water (1 cal/g.°C)
According to the law of conservation of energy, the sum of the heat released by the water () and the heat absorbed by the reaction () is zero.
Answer:
= 374.90 kPa
Calculation:
As we know atm and kiloPascal are related to each other as,
1 atm = 101.325 kPa
So,
3.70 atm = X
Solving for X,
X = (3.70 atm × 101.325 kPa) ÷ 1 atm
X = 374.90 kPa
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