Same as the other person most likely would be 20 times louder as your answer
The answer on Edge would be (A.)= Larger and Cooler ! I'm doing the same thing as y'all. Good luck everyone.
In this problem, we apply the equation regarding kinematics expressed as vf^2 = v0^2 + 2as vf eventually becomes zero because the ball stops in the end. a = -9.8 m/s2s = 2 metres this time
This gives initial velocity, vo equal to 6.26m/s
now 6.26-(-8.85) = 15.11m/s
change in velocity/change in time = average acceleration 15.11/(12/1000) = 1259.167 m/s^2
