Answer:
Kindly check explanation
Step-by-step explanation:
A.)
Differentiating based on the shape of the box and whisker plot.
The first plot, named shrella depicts a skewed distribution, (negative skew) highlighted by the long whisker (tail) to the left with the median also shifting towatds to the right of the box away from the box center. This could mean that the time difference between the coins aren't even and older coins seem to exhibit a larger time gap than newer coins.
The second plot however. VENITA, depicts a distribution which could be described as normal, as the whiskers are aodt of equal length and the median centered in the middle of the box. This could mean that Venita's coins are evenly spread out based time.
B.)
As for the overall spread, Shrella's plot covers a wider range, hence (larger spread) than Venita's plot. Thanks to the long whiskers in Shrella's plot.
For the spread within the boxes, Venita's plot has a larger within box spread than Shrella. With Venita's plot has a wider box tham Shrella's box plot.
C)
The appropriate measure of centre to be used is the median which is denoted by the vertical line in between the box. Shrella's plot has a median value of about 68 while Venita's has a median value of 60. The median value are still s bit close or similar.
Answer:
7/12
Step-by-step explanation:
Answer: Since her art and music sections each only had half the number of sheets of paper as a core subject, together the two sections had the same amount of paper as a core subject. Therefore, it is almost like her notebook had five core subjects, rather than four core subjects and two electives. If she divided the 200 sheets equally among the five core subjects, there would be 200 ÷ 5 = 40 sheets in each section. Now we can see that art would actually have half of this amount, or 20 sheets of paper.
Answer:
<em>Option D</em>
Step-by-step explanation:
Assume that these polygons were similar. You could tell that if they were, ABCD ~ EFGH, and is already noted by the answer choices. We can conclude that AB ~ EF, CD ~ GH and so on. To prove that these shapes are similar, we must form a like proportionality among these side;
As the proportions we formed were to equal to one another,<em> the solution must be option D!</em>
No if it was, the football would keep going up forever and keep going up faster as it was released
physics and common sense tells us that there is air resistance to slow the rise of the football
not exponential