Answer:
21+12i i hope this will help you
Step-by-step explanation:
(3-4i)(1+5i)-(2-i)
=[3(1+5i)-4i(1+5i)]-(2-i)
=[3+15i-4i-20i²]-(2-i)
=(3+11i-20i²)-(2-i)
opening brackeys
=3+11i-20i²-2+i
=3+11i+1i-20i²-2
as we know that i²=-1
=3-20(-1)-2+12i
=3+20-2+12i
=21+12i
He has to mow 14 yard to get at least 200 but he will have 10 extra dollars.
Answer:
The probability you see a dolphin or a whale on both days is 0.64
Step-by-step explanation:
Consider the provided information.
It is given that the brochure claims an 80% chance of siting a dolphin or a whale.
The provided claims can be written as: 80% or 0.80
Let say first day you see a dolphin or a whale and same happen on the next day.
Thus, the probability is:
0.80 × 0.80 = 0.64
Probability of see them on both days is 0.64
Hence, the probability you see a dolphin or a whale on both days is 0.64
Answer:
Kindly check explanation
Step-by-step explanation:
Given the following :
40 metres covered in 6 seconds
Max speed attained after 6seconds
75 meters covered after 11 seconds
Average Speed for first 40 meters :
Speed = distance / time
Speed = 40m / 6s
Speed = 6.67m/s
To obtain the maximum speed :
Next (75 - 40) meters = 35 meters was covered in (11 - 6)seconds = 5 seconds
Speed at this point is maximum :
Hence, maximum speed = (35m / 5s) = 7m/s
Suppose, Manuel runs for an additional z seconds after reaching max speed :
Distance from starting line 6+z seconds after race started?
Distance after 6 seconds = 40 metres
Distance after z seconds = 7 * z
Total distance = (40 + 7z)
What is Manuel's distance from the starting line x seconds after the race started (provided x≥6x)?
Distance for first 6 seconds = 40 meters + distance covered after 6 seconds = (7 * (x-6))
40 + 7(x - 6)
