The line of symmetry is 1
No, it won’t work. The greatest common factor between 45 and 27 is 9, but 45-27=18. So it cannot work.
A.)
<span>s= 30m
u = ? ( initial velocity of the object )
a = 9.81 m/s^2 ( accn of free fall )
t = 1.5 s
s = ut + 1/2 at^2
\[u = \frac{ S - 1/2 a t^2 }{ t }\]
\[u = \frac{ 30 - ( 0.5 \times 9.81 \times 1.5^2) }{ 1.5 } \]
\[u = 12.6 m/s\]
</span>
b.)
<span>s = ut + 1/2 a t^2
u = 0 ,
s = 1/2 a t^2
\[s = \frac{ 1 }{ 2 } \times a \times t ^{2}\]
\[s = \frac{ 1 }{ 2 } \times 9.81 \times \left( \frac{ 12.6 }{ 9.81 } \right)^{2}\]
\[s = 8.0917...\]
\[therfore total distance = 8.0917 + 30 = 38.0917.. = 38.1 m \] </span>
Studio = 7 yards by 4 yards
Area = 7*4 = 28 square yards.
Area of square carpet = 1 yard * 1 yard = 1 square yard
Number needed = Area of studio / Area of square carpet = 28 / 1 = 28
Number needed = 28
Answer: (5,8)
Step-by-step explanation:
So this is a matter of using a system of linear equations
To start if a total of 13 people got a ticket then we know that
x+y=13
x and y being explained in the problem
then if adult tickets are $40 and children tickets are $20 and the total cost is 360 we can set up the next equation
40x+20y=360
<em>If you were to plug in 1 lets say into x that means that 1 person bought a ticket for $40 this shown by 40 (1) this is the same premise for the childrens tickets.</em>
now we have
x+y=13
40x+20y=360
now we can solve by eliminating one of the variables this is done by either getting rid of the x or y and solving for the other. I solved for the y value first this looks like
-40(x+y=13)
40x+20y=360
Distribute the -40 to each value
giving you
-40x-40y=-520
40x+20y=360
add these together from the top down
the x's cancel leaving
-20y=-160
then isolate the y value by dividing both sides by -20
-20y/-20=-160/-20
leaving you with your y point
y=8
This is how many childrens rickets were sold now we can plug into the first linear equation
x+8=13
now easy subtration to isolate the x point
x+8-8=13-8
x=5
Finally leaving you with point (5,8)