Answer:
Here is the full proof:
AC bisects ∠BCD Given
∠CAB ≅ ∠CAD Definition of angle bisector
DC ⊥ AD Given
∠ADC = 90° Definition of perpendicular lines
BC ⊥ AB Given
∠ABC = 90° Definition of perpendicular lines
∠ADC ≅ ∠ABC Right angles are congruent
AC = AC Reflexive property
ΔCAB ≅ ΔCAD SAA
BC = DC CPCTC
If you multiplied the base times the width times the height you would get a final answer of 60m.
The correct answer is C) 71
Answer:
Those areas are: A 1 = 12, A 2 = 19
Step-by-step explanation:
The area of shape 1 : it consists of 1 square + 4 right triangles
Area of the square: A = a², area of the triangle: A = 1/2 · a · h
A 1 = 2² + 4 · 1/2 · 2 · 2 = 4 + 8 = 12
The area of shape 2 : it consists of 2 isosceles triangles
A 2 = 1/2 · 2 · 4 + 1/2 · 6 · 5 = 4 + 15 = 19
Answer:
3b - 
b
Step-by-step explanation:
Let the number be "b"
So the expression would be:
3b - b
