Answer:
Step-by-step explanation:
Distributive property: a(b +c) = (a*b) + (a*c)
45 = 40 + 5
5* 45 = 5* (40 + 5)
= 5*40 + 5*5
= 200 + 25
= 225
Answer:
8 inches.
Step-by-step explanation:
From the statement we have that they first made two identical square pyramids, each with a base area of 100 square inches.
Ab = s ^ 2 = 100
Therefore each side would be:
s = (100) ^ (1/2)
s = 10
So, side of the square base = 10 inches
Then they tell us that they glued the bases of the pyramids together to form the precious stone. The surface area of the gemstone is 520 square inches, so for a single pyramid it would be:
Ap = 520/2 = 260
For an area of the square pyramid we have the following equation:
Ap = 2 * x * s + s ^ 2
Where x is the height of each triangular surface and s is the side of the square base
Replacing we have:
260 = 2 * x * 10 + 10 ^ 2
20 * x + 100 = 260
20 * x = 160
x = 160/20
x = 8
Therefore, the value of x is 8 inches.
Answer:
Function:
Amount earned for 10 hours of work:
Step-by-step explanation:
Let be "x" the number of hours worked on a project and "y" the total amount Luigi charges for a project.
Based on the data given in the exercise, you can identify that:
- $140 is a fixed amount.
- For each hour worked on the project, Luigi charges $25. This can be expressed as:
Then, the total amount he charges for a project is the sum of $140 and . This can be represented with the following function:
To calculate the amount of money earned for 10 hours of work, you must substitute into the function and evaluate. Then:
Answer:
$4
Step-by-step explanation:
Trey sold his $80 hockey stick for 25% less. This means that he received 75% of the $80. Convert the percentage to a decimal, so it will be .75. Multiple .75 by $80 and you will get the final answer which is $60.
Brandon sold his $80 hockey stick for 30% less. This means that he received 70% of the $80. Convert the percentage to a decimal, so it will be .70. Multiple .70 by $80 and you will get the final answer which is $56.
Trey received $4 more for his hockey stick.