C) closest to 2/5.
2/3 is bigger than half 2/10 would be like less than 1/4
9514 1404 393
Answer:
14 +2i
Step-by-step explanation:
For this sort of problem, you can treat i as though it were a variable. Combine like terms.
(8 -7i) +(6 +9i) = (8 +6) +(-7 +9)i
= 14 +2i
Answer:
Option C.
Step-by-step explanation:
We need to translate each phrase and find the different expression.
"+" sign is used for sum, more and total.
Twice means two times of a number.
Let n be the unknown number.
Two more than a number = n+2
The total of n and 2 = n+2
Twice the number n = 2n
Sum of n and 2 = n+2
From the above expressions it is clear that only 2n is different from other.
Therefore, the correct option is C.
![x^ \frac{m}{n} = \sqrt[n]{x^m}](https://tex.z-dn.net/?f=x%5E%20%5Cfrac%7Bm%7D%7Bn%7D%20%3D%20%5Csqrt%5Bn%5D%7Bx%5Em%7D%20)
![((7x^3)(y^2))^ \frac{2}{7} = \sqrt[7]{((7x^3)(y^2))^2}](https://tex.z-dn.net/?f=%20%28%287x%5E3%29%28y%5E2%29%29%5E%20%5Cfrac%7B2%7D%7B7%7D%20%3D%20%5Csqrt%5B7%5D%7B%28%287x%5E3%29%28y%5E2%29%29%5E2%7D%20)
=![\sqrt[7]{((7x^3)^2(y^2)^2)}](https://tex.z-dn.net/?f=%20%5Csqrt%5B7%5D%7B%28%287x%5E3%29%5E2%28y%5E2%29%5E2%29%7D%20)
=![\sqrt[7]{((7^2x^6)(y^4))}](https://tex.z-dn.net/?f=%20%5Csqrt%5B7%5D%7B%28%287%5E2x%5E6%29%28y%5E4%29%29%7D%20)
=![\sqrt[7]{((49x^6)(y^4))}](https://tex.z-dn.net/?f=%20%5Csqrt%5B7%5D%7B%28%2849x%5E6%29%28y%5E4%29%29%7D%20)
=![\sqrt[7]{49x^6y^4}](https://tex.z-dn.net/?f=%20%5Csqrt%5B7%5D%7B49x%5E6y%5E4%7D%20)
