39.65 is the approximate value of arccos0.77
From the information given about the square pyramid, the maximum base length of the building is 67.42 cm.
<h3>How do you determine the maximum side length?</h3>
We are given the following details are:
Base = b
Slant height (l) = 5b
The lateral surface area is calculated using:
L = 2bl
So, we have:
L = 2 * b * 5b
Evaluate the product
L = 10b²
The total surface area is calculated using:
T = L + b²
So, we have:
T = 10b² + b²
Evaluate the sum
T = 11b²
Recall that the maximum surface area is 50,000 square feet
So, we have:
11b² = 50000
Divide both sides by 11
b² = 50000/11
Taking the square root of both sides, we have
b = 67.42
Hence, the maximum base length of the building is 67.42 cm
Learn more about square pyramids at:
brainly.com/question/12146629
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If you are graphing quadratic equations of the type
ax^2 + bx + c = 0
The equation will look like a "U" <span>if "a" is positive </span>or it will look like an upside-down "U" <span>if "a" is negative </span>
Given: <span>2x-y-3=0.
find </span>equation for the line perpendicular to the given line that goes through the given point:<span>
(2;-1)koord of direction vector (i`m not know how it is called at you, because i'm from russia)</span><span>
=> (x-0)/2=(y-4)/-1 (</span>canonical <span>equation)
=>x+2y-8=0(general </span><span>equation)
</span>
<span>further:
{x+2y-8=0
{2x-y-3 =0 => y=13/5 x=14/5
(14/5; 13/5) - koord point on line
</span>|dist|=sqrt( (14/5-0)^2 + (13/5-4)^2 ) = sqtr(7.72) = 2.78
Удачи!
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