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2 years ago

Show work on this pls

Mathematics

1 answer:

stepan [7]2 years ago

4 0

Answer:

6.29

Step-by-step explanation:

so you know that the unknown side which is 7x + 27 equals 71.

You can begin by subtracting 27 from 71 which will give you 44.

you then know that 44 = 7x

then you just have to do 44 divided by 7 to find x which isss...

look above at answer

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Arielle wants to make a circular garden. She has enough fencing for a garden circumference of 15 feet. There is a 7-foot gap bet

lesantik [10]

Answer:

yes

Step-by-step explanation:

We need to check if the circle with a circumference of 15 feet is smaller then 7 feet. If so it possible.

Formule for circular circumference = pi * diameter, which should be 15.

So pi * d =15

There fore d = 15/pi

d = 4.77464829275686 feet, which is smaller then 7 feet, so it will fit easilly.

3 0

2 years ago

Use the diagram to complete the statement. Triangle J K L is shown. Angle K J L is a right angle. Angle J K L is 52 degrees and

zzz [600]

Answer:

$\bold{sin(38^\circ)=cos(52^\circ)}$

Step-by-step explanation:

Given that $\triangle KJL$ is a right angled triangle.

$\angle JKL = 52^\circ\\\angle KLJ = 38^\circ$

and

$\angle KJL = 90^\circ$

Kindly refer to the attached image of $\triangle KJL$ in which all the given angles are shown.

To find:

sin(38°) = ?

a) cos(38°)

b) cos(52°)

c) tan(38°)

d) tan(52°)

Solution:

Let us use the trigonometric identities in the given $\triangle KJL$ .

We have to find the value of sin(38°).

We know that sine trigonometric identity is given as:

$sin\theta =\dfrac{Perpendicular}{Hypotenuse}$

$sin(\angle JLK) = \dfrac{JK}{KL}\\OR\\sin(38^\circ) = \dfrac{JK}{KL}$ ....... (1)

Now, let us find out the values of trigonometric functions given in options one by one:

$cos\theta =\dfrac{Base}{Hypotenuse}$

$cos(\angle JLK) = \dfrac{JL}{KL}\\OR\\cos(38^\circ) = \dfrac{JL}{KL}$ ....... (2)

By (1) and (2):

sin(38°) $\neq$ cos(38°).

$cos(\angle JKL) = \dfrac{JK}{KL}\\OR\\cos(52^\circ) = \dfrac{JK}{KL}$ ...... (3)

Comparing equations (1) and (3):

we get the both are same.

$\therefore \bold{sin(38^\circ)=cos(52^\circ)}$

6 0

2 years ago

Which values are solutions to the inequality below? <br><br>Check all that apply.<br><br>x2 < 81

11111nata11111 [884]

A(6) and D(-4) are solutions to the equations

(6)^2 < 81 | 36 < 81

(-4)^2 < 81 | 16 < 81

5 0

2 years ago

Read 2 more answers

Which equation represents a line which is parallel to the line y=-3/4 x -2

garri49 [273]

Answer:

Any equation with the same slope: for example y=-3/4x+10

Step-by-step explanation:

6 0

2 years ago

Read 2 more answers

If √2 = 1.414 then the value of 5+√2 / 5-√2 is

Gala2k [10]

Answer:

1.787

Step-by-step explanation:

$\\ \sf \frac{5 + \sqrt{2} }{5 - \sqrt{2} } \times \frac{5 + \sqrt{2} }{5 + \sqrt{2} }$

$\\ \sf = \frac{(5 + \sqrt{2}) }{5 - \sqrt{2} } \times \frac{(5 + \sqrt{2}) }{5 + \sqrt{2} }$

$\\ \sf = \frac{25 + 5 \sqrt{2 } + 5 \sqrt{2} + 2 }{( {5})^{2} - ( \sqrt{ {2}})^{2} }$

$\\ \sf = \frac{27 + 10 \sqrt{2} }{25 - 2}$

$\\ \sf = \frac{27 - 10 \sqrt{2} }{23}$

Now putting the value of√2

$\\ \sf = \frac{27 + 10 \times 1.414}{23}$

$\\ \sf = \frac{27 + 14.14}{23}$

$\\ \sf = \frac{41.14}{23}$

$\\ \sf = 1.787$

3 0

2 years ago