This problem uses the relationships among current
I, current density
J, and drift speed
vd. We are given the total of electrons that pass through the wire in
t = 3s and the area
A, so we use the following equation to to find
vd, from
J and the known electron density
n,
so:
<span>The current
I is any motion of charge from one region to another, so this is given by:
</span>
The magnitude of the current density is:
Being:
<span>
Finally, for the drift velocity magnitude vd, we find:
</span>
Notice: The current I is very high for this wire. The given values of the variables are a little bit odd
You are true, Stokey. The correct choice is<em> (c)</em>.
If you think about it a little bit more, you'll realize that "side to side" is also a horizontal motion.
Anyway, the question told us that we're only talking about 2 dimensions. Well, the The measurements in the 2 dimensions are the x and the y . If there were a z measurement, that would be the 3rd dimension.
The answer is D.
Hope it helps!
Answer:
35.2 ps
Explanation:
Hello!
A US short ton is equal to 2 000 pounds, therefore:
2.25 tons = 4500 pounds
Now lets convert the area of each tire footprint:
1 cm = 0.393701 in
12.5 cm = 4.92126 in
16.5 cm = 6.49607 in
Therefore, the area of the footprint is: 31.9688 in^2
Then, the pressure exerted by the car is given by the weigth devided by the total area, that is 4 times the area of the footprint :
4500 /(4 * 31.9688) psi = 35.1906 psi
Rounding to the first tenth
35.2 psi