The reaction between methane gas and chlorine gas to form hydrogen chloride and carbon tetrachloride, all in their gaseous form can be expressed through the chemical reaction below.
CH₄ + 4Cl₂ --> 4HCl + CCl₄
Let us assume that all the involved gases behaves ideally such that each mole of the gas is equal to 22.4 L.
Through proper dimensional analysis, the volume of the produced hydrogen chloride is calculated,
V(HCl) = (1.69 mL CH₄)(1 L CH₄/ 1000 mL CH₄)(1 mol CH₄/22.4 L CH₄)(4 mols HCl/1 mol CH₄)(22.4 L HCl/1 mol HCl)(1000 mL/1 L)
V(HCl) = 6.76 mL
<em>ANSWER: 6.76 mL</em>
Are there answer choices or is it just right it your self?
Yeah so you have to start of with converting your first two values into moles (forget the third one)
97.5 g NO * 1 mol/30.01 g NO = 3.25 moles NO
88.0 g O2 * 1 mol/16.00 g O2 = 5.5 moles O2
now we can find the limiting reactant by checking for the amount of product each reactant should give us by using molar ratios
3.25 mol NO * 2 mol NO2/2 mol NO = 3.25 mol NO2
5.5 mol O2 * 2 mol NO2/ 1 mol O2 = 11
so NO is the limiting reactant since it produces less product/gets used up quicker
3.25 mol NO * 2 mol NO2/2molNO = 3.25 mol NO2
so this is our theoretical yield and the question provides us with the actual yield (2.68 moles). since the actual yield is given in moles, we don't have to convert to grams. our percent yield formula goes like: actual yield/theoretical yield * 100
2.68 mol/3.25 mol * 100 = 82.46%
I believe what you are trying to ask here is the balanced chemical reaction. We first identify the chemical formula of the substances.
Lead(II) sulfide = PbS
Oxygen = O2
Lead(II) oxide = PbO
Sulfur dioxide = SO2
The balanced chemical reaction is written as:
PbS + 3/2O2 = PbO + SO2
