Answer:
Explanation:
The table that shows the pattern for this question is:
Time (year) Population
0 40
1 62
2 96
3 149
4 231
A growing exponentially pattern may be modeled by a function of the form P(x) = P₀(r)ˣ.
Where P₀ represents the initial population (year = 0), r represents the multiplicative growing rate, and P(x0 represents the population at the year x.
Thus you must find both P₀ and r.
<u>1) P₀ </u>
Using the first term of the sequence (0, 40) you get:
P(0) = 40 = P₀ (r)⁰ = P₀ (1) = P₀
Then, P₀ = 40
<u> 2) r</u>
Take two consecutive terms of the sequence:
- P(1) / P(0) = 40r / 40 = 62/40
You can verify that, for any other two consecutive terms you get the same result: 96/62 ≈ 149/96 ≈ 231/149 ≈ 1.55
<u>3) Model</u>
Thus, your model is P(x) = 40(1.55)ˣ
<u> 4) Population of moose after 12 years</u>
- P(12) = 40 (1.55)¹² ≈ 7,692.019 ≈ 7,692, which is round to the nearest whole number.
-19, -12, 1/2, 1, 5, 12 ----> least to greatest
12, 5, 1, 1/2, -12, -19 ----> greatest to least
Do the same as the last one, starting with the largest negative number, and ending with the largest positive number. The only difference in this case is that it is greatest to least. I tend to go from least to greatest first and then flip it around to get greatest to least (:
Rachel would take 30 minutes to run in 4miles
Step-by-step explanation:
50% interest annually.
that means he gets 50% interest of the invested capital every year.
and that means he gets 50% of $70 in one year.
70 = 100%
1% = 100%/100 = 70/100 = $0.70
50% = 1%×50 = 0.7 × 50 = $35
he will earn $35 interest in one year.
as you noticed: 50% simply means 1/2 (as 100% stands for the whole).