1 mole of h3bo3...........6.023*10²³ each h and B and 0 so we will have 3hydrogen+ 1 B+3 oxygen = 7*6.023*10²³ atoms
1 mole .......7*6.023*10²³atoms
4 moles ........x atoms
x=4*7*6.023*10²³.
ClBr, two nonmetals
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Answer:
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Explanation:
There are 12 carbon atoms, 22 hydrogen atoms, and 11 oxygen atoms in one molecule of C12H22O11.
In five molecules there are 60 carbon atoms, 110 hydrogen atoms, and 55 oxygen atoms.