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2 years ago

1/2 in decimal form

Mathematics

1 answer:

dangina [55]2 years ago

8 0

0.50 0.24 0.375 1.25 1.5

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Calculate a vector c in the same direction of the vector a and that has the same length as the vector b

Viktor [21]

For any scalar $t>0$ , $t\vec a$ is a vector pointing in the same direction as $a$ .

To force this vector to have the same length as another vector $\vec b$ , first normalize $t\vec a$ by dividing it by its norm,

$\dfrac{t\vec a}{\|t\vec a\|}=\dfrac{t\vec a}{t\|\vec a\|}=\dfrac{\vec a}{\|\vec a\|}$

then multiply this vector by the norm of $\vec b$ , so that

$\vec c=\dfrac{\|\vec b\|}{\|\vec a\|}\vec a$

To confirm that $\vec c$ has the same length as $\vec b$ :

$\|\vec c\|=\left\|\dfrac{\|\vec b\|}{\|\vec a\|}\vec a\right\|=\dfrac{\|\vec b\|}{\|\vec a\|}\|\vec a\|=\|\vec b\|$

8 0

2 years ago

I NEED HELP ASAP PLEASE NO LINKS !!!

My name is Ann [436]

25-9=16 so 16 is the answer

8 0

2 years ago

PLZ CAN SOMEONE ANSWER THIS !!

Cerrena [4.2K]

Answer:

(-4,2)

Step-by-step explanation:

First we have to find a common multiple to use to add and find the system of equations. We need to eliminate one of the variables in order to solve.

Since 5 * 3 = 15, and 3 * -5 = 15, -15x and 15x will cancel each other out. Therefore x will be eliminated.

Before:

5x + 2y = -16

3x + 7y = 2

After:

15x + 6y = -48 <----------Now we solve for y

-15x + -35y = -10

+----------------------

-29y = -58

-29 -29

y = 2

Now what we do is we choose and equation and solve for x, since it is still unknown. Any equation is fine but I will choose the second one since it has easy numbers.

3x + 7y = 2

3x + 7(2) = 2

3x + 14 = 2

-14 -14

----------------------

3x = -12

3 3

x = -4

Therefore our final answer is (-4,2)

5 0

2 years ago

Help answering this simple Series Question? I don't know what I did wrong!

Tatiana [17]

Looks like you just evaluated the summand for the given value of $n$ , whereas the question is asking you to find the value of the sum for the first $n$ terms.

Let $S_k=\displaystyle\sum_{n=1}^k\frac3{(-2)^n}$ . Then $S_k$ is the $k$ th partial sum.

$S_1$ happens to be the first term in the series, which is why that box is marked correct:

$S_1=\displaystyle\sum_{n=1}^1\frac3{(-2)^n}=\frac3{(-2)^1}=-1.5$

But the next partial sum is not correct:

$S_2=\displaystyle\sum_{n=1}^2\frac3{(-2)^n}=\frac3{(-2)^1}+\frac3{(-2)^2}=-0.75$

and this is not the same notion as the second term (which indeed is 0.75) in the series.

5 0

2 years ago

I need help with number 1

Marianna [84]

Answer:

1a. 0< -4 false

1b. -3> or = -7 true

1c. 4<= -1/2 false

8 0

2 years ago