Answer: 4=-2x -1 and y=-1 2x
The answer to the first question of the attached document is option 1. We obtain the answer subtracting the term n from the series with the term n-1.For example:
-3 - (- 5) = 2
-1 - (- 3) = 2
1 - (- 1) = 2
So you can see that the common difference is the 2.
The answer to the second question is option 3:
y = | x + 7 |
We can confirm it by substituting values in the equation.
For example:
if we do y = 0 then x = -7
if we do x = 0 then y = 7.
As corresponds in the graph shown.
Remember also that as a general rule yes to the equationy = | x | whose vertex is in the point (0,0) we add a positive real number "a" of form y = | x + a | then the graph of y = | x | will move "to" units in the negative direction of x.
The answer to the third question is option 4.
The quotient of x and "and" is constant.
k = y / x
Rewriting:
y = kx
You can see that it corresponds to the equation of a line that passes through the origin, this means that and is proportional to x and both vary directly
Answer:
0
Step-by-step explanation:
To find the slope between the two given points, you can use the given formula for the slope between two points.
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<h3>given</h3>
The points are (x1, y1) = (-3, 2) and (x2, y2) = (4, 2).
The formula is ...
slope = (y2 -y1)/(x2 -x1)
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<h3>use the formula</h3>
Substituting the given values into the formula gives ...
slope = (2 -2)/(4 -(-3)) = 0/7 = 0
The slope of the line is zero.
<span>Slope of JK=((-1)-2)/(4-(-3)=-3/7
Slope of KL=((-5)-(-1)/(2-4=2
Slope of LM=((-2)-(-5))/(-5-2)=-3/7
Slope of MJ=(2-(-2))/((-3)-(-5))= 2
JK is parallel to LM and KL is parallel to MJ. Therefore JKLM is a parallelogram.</span>
