Answer:
0.30
Step-by-step explanation:
Probability of stopping at first signal = 0.36 ;
P(stop 1) = P(x) = 0.36
Probability of stopping at second signal = 0.54;
P(stop 2) = P(y) = 0.54
Probability of stopping at atleast one of the two signals:
P(x U y) = 0.6
Stopping at both signals :
P(xny) = p(x) + p(y) - p(xUy)
P(xny) = 0.36 + 0.54 - 0.6
P(xny) = 0.3
Stopping at x but not y
P(x n y') = P(x) - P(xny) = 0.36 - 0.3 = 0.06
Stopping at y but not x
P(y n x') = P(y) - P(xny) = 0.54 - 0.3 = 0.24
Probability of stopping at exactly 1 signal :
P(x n y') or P(y n x') = 0.06 + 0.24 = 0.30
Answer:
√95 cm
Step-by-step explanation:
To solve, you need to use the pythagorean theorem, or a^2 + b^2 = c^2
The hypotenuse is the c and let one leg be b. You can write:
a^2 + 7^2 = 12^2
a^2 + 49 = 144
Now, you need to solve for a:
a^2 = 144 - 49
a^2 = 95
a = √95 cm, or about 9.75cm
Answer:
d) 5/12
Step-by-step explanation:
A probability is the number of desired outcomes divided by the number of total outcomes.
Drinks:
Five diet, 10 regular.
Probability of a regular drink:
10/(10+5) = 10/15 = 2/3
Regular bag of chips:
6 fat-free, 10 regular
Probability of a regular bag of chips:
10/(10+6) = 10/16 = 5/8
What is the probability that you will buy a regular drink and a regular bag of chips?
Drink and chips are independent events, which means that we just multiply the probabilities. So
The correct answer is given by option d.
Because it was being impeached