The value of y is 5
<h3>How to determine the value </h3>
From the given line, it can be concluded that:
The segment RT is divided into RS and ST
But we have the following parameters
The length of the sides are:
Since RT is RS added to ST:
We have;
RT = RS + ST
substitute the values
43 = 4y + 4 + 3y + 4
collect like terms
43 = 4y + 3y + 4 + 4
Add like terms
43 = 7y + 8
43 = 7y + 8
Make '7y' subject of formula
7y = 43 - 8
7y = 35
Make 'y' the subject of formula
y = 35/ 7
y = 5
Thus, the value of y is 5
Learn more about segments here:
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Answer:
Subtract
1
1
1
from both sides of the equation
2
+
1
=
1
1
2
+
1
−
1
=
1
1
−
1
2
Simplify
3
Divide both sides of the equation by the same term
4
Simplify
Solution
=
5
Step-by-step explanation:
Begin by finding the lowest point the quadratic equation can be, the vertex;
x²-1= is just a translation down of the graph x²
vertex; (0, -1) and since the graph of x² would extend to infinity beyond that point, we can say {x| x≥0} for domain and {y| y≥-1}.
For the linear equation, it is possible to have all x and y values, therefore range and domain belong to all real numbers.
Hope I helped :)
See the attached picture for the solution:
