We have 60 gallons of 20% antifreeze.
How much 70% antifreeze do we add to get 60% antifreeze?
We'll make "x" the gallons of 70% we must add.
.20 * 60 + .70 x = .60 * (60 + x)
12 + .70x = 36 + .60x
.10x = 24
x = 240 gallons of 70% antifreeze.
Source
1728.com/mixture.htm (see example B)
A measurement that closely agrees with an accepted value is best described as a numerical
Answer:
The answer to your question is below
Step-by-step explanation:
csc α - cot α =
Work with the left part
Simplify
Multiply by the reciprocal
Simplify
Remember that
sin²α = 1 -cos²α
Substitute the previous equation
Simplify
The identity i proved.
Answer:
x = 7.
Step-by-step explanation:
-5x + 18 = 3x - 38
18 + 38 = 3x + 5x
56 = 8x
x = 7.