Question

Three-fourths of the sum of six times a number and twelve distribute

Answer 1

Answer:

Step-by-step explanation:

Let x be the number.

6 times the number = 6*x = 6x

Sum of 6 times of a number and twelve = 6x + 12

Three-fourths of the sum of 6 times of a number and twelve = $\frac{3}{4}(6x +12)$

$\frac{3}{4} ( 6x + 12) = \frac{3}{4}*6x + \frac{3}{4}*12$

                $= \frac{3}{2}*3x + 3*3\\\\=\frac{9}{2}x + 9$