<span>The
third root of the given complex number 27(cos(pi/5)+isin(pi/5)) is <span>3(cos(pi/15)+i sin(pi/15))
</span>The solution would be like this
for this specific problem:</span>
<span>2^5 =
32 so you need a 2 out front the 5th root of cos(x) + i sin(x) is
cos(x/5) + i sin(x/5). Additionally, 5 roots are located at even
intervals around the circle. They are spaced every 2 pi/5 or 6 pi/15 radians.
</span>
<span>Roots
are located at pi/15, pi/15+ 10pi/15 = 11 pi/15 and pi/15+ 20pi/15 = 21 pi/15
(or 7 pi /5 ).</span>
Answer:
The GCF is 1 and the LCM 280
Step-by-step explanation:
I did this on a test and got it right
Answer:
Wait what is the question the question you put in was
"PLEASE ANSWER ILL MAKE YOU BRAINLIEST 2 questions"
Step-by-step explanation:
Is that a question or answer? If it's a question that's the right answer.
Answer: it’s 55/100 percent
