Find the value of 18 ÷ 9 ∙ 3. 6

write an expression for the calculation 5 times the number 25 and then subtract the quotient of 14 and 7

gavmur [86]

(5*5=25)-(14+7=21) which is basically

25-21

5 0

2 years ago

Courtney walks 1 mph slower than Brandi does. In the time that it takes Brandi to walk 6.5 mi, Courtney walks 5 mi. Find the spe

posledela

Answer:

Courtney's walking speed = 3.33mph

Brandi's walking speed = 4.33 mph

Step-by-step explanation:

Let x = Courtney's walking speed

then

(x + 1) = Brandi's walking speed

:

Time = Distance/speed

Brandi walks 6.5 mi time = Courtney walks 5 mi time

6.5/x + 1 = 5/x

Cross multiply

6.5x= 5(x+1)

6.5x= 5x + 5

6.5x - 5x = 5

1.5x = 5

x = 5/1.5

x = 3.33 mph is Courtney's walking speed

Note that:

(x + 1) = Brandi's walking speed

3.33mph + 1 = 4.33mph

Therefore,

Courtney's walking speed = 3.33mph

Brandi's walking speed = 4.33 mph

4 0

2 years ago

Write an equation to describe the sequence below use and to represent the position of a term in the sequence where n equals one

Katen [24]

Answer:

an = 4^(n-1)

Step-by-step explanation:

The three given terms have a common ratio of 4:

4/1 = 16/4 = 4

So, this can be described by the function for a geometric sequence:

an = a1×r^(n -1)

where an is the n-th term, a1 is the first term (1) and r is the common ratio (4).

an = 1×4^(n-1)

an = 4^(n -1) . . . . . simplified

6 0

3 years ago

Quadratic equations and complex numbers PLEASE HELPPPP ASAP

kondor19780726 [428]

we are given

$27x^3-1=0$

we can also write it as

$(3x)^3-(1)^3=0$

now, we can use factor formula

$a^3-b^3=(a-b)(a^2+ab+b^2)$

we can use above formula

we get

$(3x)^3-(1)^3=(3x-1)((3x)^2+3x\times 1+(1)^2)$

now, we can simplify it

$27x^3-1=(3x-1)(9x^2+3x+1)$

now, we can set it to 0

$27x^3-1=(3x-1)(9x^2+3x+1)=0$

and then we can solve for x

$(3x-1)(9x^2+3x+1)=0$

$3x-1=0$

$x=\frac{1}{3}$

$9x^2+3x+1=0$

now, we can use quadratic formula

$x=\frac{-b\pm \sqrt{b^2-4ac}}{2a}$

now, we can plug values

and we get

$x=\frac{-3\pm \sqrt{3^2-4\cdot \:9\cdot \:1}}{2\cdot \:9}$

$x=-\frac{1}{6}+i\frac{\sqrt{3}}{6},\:x=-\frac{1}{6}-i\frac{\sqrt{3}}{6}$

So, we will get solution as

$x=\frac{1}{3},\:x=-\frac{1}{6}+i\frac{\sqrt{3}}{6},\:x=-\frac{1}{6}-i\frac{\sqrt{3}}{6}$ ...............Answer

5 0

2 years ago

Converges and diverged part 4

Allushta [10]

Answer:

Diverges; no sum

Step-by-step explanation:

This is comparable to:

$\sum_{k=1}^\infty a \cdot r^{k-1}$ where:

r is the common ratio and $a$ is the first term.

The series converges to:

$\text{First term}\cdot \frac{1}{1-\text{common ratio}}$

if the ratio's absolute value is less than 1.

This is a geometric series.

The common ration is -1.04 .

The first term in the series is 0.001.

Since the absolute value of -1.04 is 1.04>1, the series diverges.

4 0

2 years ago