The ball is hit with an initial vertical velocity of
(147 m/s) sin(38º) ≈ 90.5 m/s
Recall that
<em>v </em>² - <em>u </em>² = 2 <em>a</em> ∆<em>y</em>
where <em>u</em> and <em>v</em> are initial and final velocities, respectively; <em>a</em> is acceleration; and ∆<em>y</em> is displacement.
Vertically, the ball is in freefall, so it is only subject to acceleration due to gravity, with magnitude <em>g</em> = 9.80 m/s² in the downward direction. At its maximum height, the ball has zero vertical velocity (<em>v</em> = 0) and the displacement is equal to the maximum height, so
0² - (90.5 m/s)² = 2 (-<em>g</em>) ∆<em>y</em>
∆<em>y</em> = (90.5 m/s)² / (2<em>g</em>)
∆<em>y</em> ≈ 418 m