Answer:
top right corner
Step-by-step explanation:
1) the green line
- straight line
- shaded region is below the line
thus, y ≤ 3
2) the blue line
- straight line
- shaded region is below the line
thus, y ≤ x-2
3) the red line
- dotted line
- shaded region is above the line
thus, y > -x+5
4) the x-axis
- straight line
- shaded region is above the line
thus, y ≥ 0
Answer:
y = (-2/5)x - 2
Step-by-step explanation:
One way to attack this problem is to interchange the coefficients of x and y and change the sign of one to +: 5x - 2y = -6 becomes 2x + 5y = c. Solving for the slope, m, we get 5y = -2x + c first, and then y = (-2/5)x + D.
Subbing 5 for x and -4 for y, we now have -4 = (-2/5)(5) + D.
Then -4 = -2 + D, so that D = -2.
The desired equation is thus y = (-2/5)x - 2.
Check: Does this pass through (5, -4)? Is -4 = (-2/5)(5) - 2 true? Yes.
Is the slope -2/5 the negative reciprocal of 5/2? Yes, it is.
From these -Tx+y=S. If -T=Q/R, then y=-Qx/R+S, so Ry=-Qx+RS, Qx+Ry=RS=S.
If R is not equal to 1, or S is non-zero, the equations are inconsistent, so there would be no solutions.
If R=1 there are an infinite number of solutions given by Qx+y=S, or y=S-Qx or y=S+Tx.
If S=0, Qx+Ry=0 or y=-Qx/R or y=Tx.
Suppose you add x liters of pure water to the 10 L of 25% acid solution. The new solution's volume is x + 10 L. Each L of pure water contributes no acid, while the starting solution contains 2.5 L of acid. So in the new solution, you end up with a concentration of (2.5 L)/(x + 10 L), and you want this concentration to be 10%. So we have
and so you would need to add 15 L of pure water to get the desired concentration of acid.
Answer:
192 in cubed
Step-by-step explanation:
Multiply 12*2= 24*8
