I think the answer should be B.
There are different kinds of math problem. There will be 11 rats in sewer #1.
<h3>What are word problem?</h3>
The term word problems is known to be problems that are associated with a story, math, etc. They are known to often vary in terms of technicality.
Lets take
sewer #1 = a
sewer #2 = b
sewer #3 = c
Note that A=B-9
So then you would have:
A=B-9
B=C- 5
A+B+C=56
Then you have to do a substitution so as to find C:
(B- 9) + (C-5) + C = 56
{ (C- 5)-9} + (C-5) + C = 56
3C - 19 = 56
3C = 75
B = C- 5
B = 25 - 5
Therefore, B = 20
A = B - 9
= 25 - 9
=11
Therefore, there are are 11 rats in sewer #1
Learn more about Word Problems from
brainly.com/question/21405634
Answer:
The correct option is;
A. All rhombuses are parallelograms. Parallelograms have 2 pairs of parallel sides. Therefore, all rhombuses have 2 pairs of parallel sides
Step-by-step explanation:
A rhombus is a quadrilateral that has all 4 sides, it has equal opposite angles and perpendicular diagonals that bisect one another as well as having a pair of opposite parallel sides making it a parallelogram
A rhombus is similar to a parallelogram which also has equal opposite and parallel sided and equal opposite angles and the diagonals of a parallelogram also bisect each other.
4(x+5y)(x-3y)
I don't know what you mean by placing the factors on the grid
Answer:
I believe that the third answer is correct..... but I'm not positive.
Step-by-step explanation:
if you get the third side of the triangle to be 71 then it would go first. Then it would go to 45-55. And lastly to 71-45