Answer:
Step-by-step explanation:
We know that the mean and the standard error of the sampling distribution of the sample proportions will be :-
, where p=population proportion and n= sample size.
Given : The proportion of students at a college who have GPA higher than 3.5 is 19%.
i.e. p= 19%=0.19
The for sample size n= 25
The mean and the standard error of the sampling distribution of the sample proportions will be :-
Hence , the mean and the standard error of the sampling distribution of the sample proportions :
Class 2 scored better on average
<h3>How to determine which class scored better on average?</h3>
The averages and the standard deviations are given as:
Class 1
Mean score = 7.8
Standard deviation = 1
Class 2
Mean score = 8.1
Standard deviation = 0.2
As a general rule, the smaller the standard deviation; the better the average
Class 2 has a smaller deviation
Hence, class 2 scored better on average
Read more about standard deviation at:
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For Sammie the equation would be S=3N.
If Nora (N) has 4 goldfish, you substitute N=4 into the previous equation to find out how many goldfish Sammie has.
> S= 3 x 4
= 12
The next part of the question is asking you how many goldfish do Sammie and Nora have in all. If Sammie has 12 goldfish and Nora has 4 goldfish, the equation would be 12 + 4= 16
The answer would be 16 goldfish in total.
31^8 (31 to the 8th power)
Answer:
LCM of 21,24 and 26 is 2184
Step-by-step explanation:
We need to find LCM of 21,24 and 26
For finding LCM divide the given numbers by a prime number if two of the numbers are divisible by that prime number
2 | 21,24,26
2 | 21,12,13
2 | 21,6,13
3 | 21,3,13
7 | 7,1,13
13 | 1,1,13
| 1,1,1
So, LCM of 21,24 and 26 is: 2 x 2 x 2 x 3 x 7 x 13 = 2184
