The average bond energy of the Xe¬F bonds in each fluoride is 132kJ/mol.
Given:
ΔH° of xenon difluoride (XeF2) = -105 kJ/mol
ΔH° of xenon tetrafluoride (XeF4)= -284 kJ/mol
ΔH° of xenon hexafluoride (XeF6) = -402 kJ/mol
The bond energy of Xe-F in XeF2 can be calculated as follows,
As we know that
ΔH° = ΔH°(bond formed) + ΔH°(bond broken)
The chemical reaction for the formation of XeF2 can be written in such a way,
Xe (g) + F2 (g) → XeF2 (g)
= [1 mol F2 (159 kJ/mol)] + [2(-Xe-F)] - 105 kJ/mol
= 159 kJ/mol + 2(-Xe-F) - 264 kJ/mol
= 2(-Xe-F)
Xe-F = 132 kJ/mol
Thus, we concluded that the average bond energy of the Xe¬F bonds in each fluoride is 132kJ/mol.
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Answer : The ratio of the protonated to the deprotonated form of the acid is, 100
Explanation : Given,
pH = 6.0
To calculate the ratio of the protonated to the deprotonated form of the acid we are using Henderson Hesselbach equation :
Now put all the given values in this expression, we get:
As per question, the ratio of the protonated to the deprotonated form of the acid will be:
Therefore, the ratio of the protonated to the deprotonated form of the acid is, 100
The option which gives the correct mole ratios is H₂S : SO₂ = 2 : 2 and O₂ : H₂O = 3 : 2
<h3 /><h3>What is Mole ratio ?</h3>
It is a conversion factor between compounds in a chemical reaction, that is derived from the coefficients of the compounds in a balanced equation
Molar ratio also known as stoichiometry is the ratio in which the reactants and products are either formed or reacted in the given equation
The balanced equation for given reaction is as follows ;
2H₂S + 3O₂ --> 2SO₂ + 2H₂O
Molar ratio can be determined by the coefficients of the compounds in the balanced reaction
Coefficient is the number in front of the chemical compound and they are as follows
- H₂S - 2
- O₂ - 3
- SO₂ - 2
- H₂O - 2
Therefore, correct option is H₂S : SO₂ = 2 : 2 and O₂ : H₂O = 3 : 2
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