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2 years ago

What is the simplified square root of -20?

Mathematics

1 answer:

poizon [28]2 years ago

5 0

Answer:

do you mean -2 $\sqrt{5}$ ?

Step-by-step explanation:

You might be interested in

If 433 = 100% then what percent does 383 equal

Goryan [66]

Answer:

88.46%

Step-by-step explanation:

433 - 383 = 50

50 ÷ 433 = 0.1154

0.1154 x 100 = 11.54%

100% - 11.54% = 88.46%

<u>Check work:</u>

433 x 88.46% = 383

5 0

2 years ago

Camden is going to invest $600 and leave it in an account for 12 years. Assuming the

UkoKoshka [18]

$~~~~~~ \textit{Continuously Compounding Interest Earned Amount} \\\\ A=Pe^{rt}\qquad \begin{cases} A=\textit{accumulated amount}\dotfill & \$920\\ P=\textit{original amount deposited}\dotfill & \$600\\ r=rate\to r\%\to \frac{r}{100}\\ t=years\dotfill &12 \end{cases}$

$920=600e^{\frac{r}{100}\cdot 12}\implies \cfrac{920}{600}=e^{\frac{3r}{25}}\implies \cfrac{23}{15}=e^{\frac{3r}{25}}\implies \log_e\left( \cfrac{23}{15} \right)=\log_e\left( e^{\frac{3r}{25}} \right) \\\\\\ \ln\left( \cfrac{23}{15} \right)=\cfrac{3r}{25}\implies 25\cdot \ln\left( \cfrac{23}{15} \right)=3r\implies \cfrac{25\cdot \ln\left( \frac{23}{15} \right)}{3}=r \\\\\\ 3.5620\approx r\implies \stackrel{\%}{3.56}\approx r$

7 0

1 year ago

What is the length of the arc on a circle with radius 21 in intercepted by a 25° angle? Round your answer to the nearest tenth.

Lana71 [14]

Answer:

Step-by-step explanation:

The formula for determining the length of an arc is expressed as

Length of arc = θ/360 × 2πr

Where

θ is the central angle formed at the center of the circle.

r represents the radius of the circle.

π represents a constant whose value is 3.14

From the information given,

r = 21 inches

θ = 25 degrees

Length of arc formed = 25/360 × 2 × 3.14 × 21 = 9.2 inches,

8 0

2 years ago

Read 2 more answers

4 is what percent of 20

neonofarm [45]

20%
Finding percentage u have to
Divide 4/20= 0.2 then multiply by 100 to get percentage which is 20%

3 0

2 years ago

Find the area between y = 8 sin ( x ) y=8sin⁡(x) and y = 8 cos ( x ) y=8cos⁡(x) over the interval [ 0 , π ] . [0,π]. (Use decima

Marina86 [1]

Answer:

0.416 au

Step-by-step explanation:

Let y1=8sin(x) and y2=8cos(x), we must find the area between y1 and y2

$\int\limits^\pi _0{(8cos(x)-8sin(x))} \, dx = 8\int\limits^\pi _0{(cos(x)-sin(x))} \, dx =\\8(sin(x)+cos(x)) evaluated(0-\pi )=\\8(sin(\pi )-sin(0))+8(cos(\pi )-cos(0))=\\8(0.054-0)+8(0.998-1)=8(0.054)+8(-0.002)=0.432-0.016=0.416$

3 0

2 years ago