Answer: yes
Step-by-step explanation:
Step-by-step explanation:
We want to find two things-- the speed of the boat in still water and the speed of the current. Each of these things will be represented by a different variable:
B = speed of the boat in still water
C = speed of the current
Since we have two variables, we will need to find a system of two equations to solve.
How do we find the two equations we need?
Rate problems are based on the relationship Distance = (Rate)(Time).
Fill in the chart with your data (chart attached)
The resulting speed of the boat (traveling upstream) is B-C miles per hour. On the other hand, if the boat is traveling downstream, the current will be pushing the boat faster, and the boat's speed will increase by C miles per hour. The resulting speed of the boat (traveling downstream) is B+C miles per hour. Put this info in the second column in the chart. Now plug it into a formula! <u>Distance=(Rate)(Time) </u>Now solve using the systems of equations!
2(4x-3) ≥ - 3(3x) + 5x
2* 4x - 2*3 ≥ - 9x + 5x
8 x - 6 ≥ -4x
8 x + 4 x ≥ 6
12 x ≥ 6
x = 6/12 divide 6/6 = 1 and 12 / 6 = 2
x = 1/2
hope this helps!
First, simplify each one.
9.98 x 10^6 = 9980000
7.3 x 10^7 = 73000000
Next, subtract the freight from the aircraft
73000000 - 9980000 = 63020000
Round the decimal point to the first significant digit, and place the amount of place values the decimal point moved to the left as a power sign, over 10.
63020000 = 6.302 x 10^7
6.302 x 10^7 is your answer
hope this helps
Answer:
1. 9-2=7
2. -6-(-4)=-2
Step-by-step explanation:
a=9
b=2
c=-6
d=-4