Find the LCM of 18e2x, e2t and y3.

A cable company charges a monthly fee for cable service plus an additional $3 for each premium channel. This is given by the fun

svlad2 [7]

Answer:

domain all real numbers

range all real numbers

the cost of his monthly cable is $40.50 when you plug in 4

3 0

2 years ago

Factor the polynomial by grouping : x^3+5x^2-6x-30

andrew-mc [135]

The idea is to pair up the terms, factor each sub-group, and then pull out the overall GCF to fully factor.

x^3+5x^2-6x-30

(x^3+5x^2)+(-6x-30)

x^2(x+5)+(-6x-30)

x^2(x+5)-6(x+5)

(x^2-6)(x+5)

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Answer: (x^2-6)(x+5)

4 0

2 years ago

GETS BRAINLIEST AND 11 PTS!

Blababa [14]

I believe the answer to this one would be 75.0%

5 0

2 years ago

If a random sample of size nequals=6 is taken from a population, what is required in order to say that the sampling distributio

goldenfox [79]

Answer:

$\bar X \sim N(\mu , \frac{\sigma}{\sqrt{n}})$

In order to satisfy this distribution we need that each observation on this case comes from a normal distribution, because since the sample size is not large enough we can't apply the central limit theorem.

Step-by-step explanation:

For this case we have that the sample size is n =6

The sample man is defined as :

$\bar X = \frac{\sum_{i=1}^n X_i}{n}$

And we want a normal distribution for the sample mean

$\bar X \sim N(\mu , \frac{\sigma}{\sqrt{n}})$

In order to satisfy this distribution we need that each observation on this case comes from a normal distribution, because since the sample size is not large enough we can't apply the central limit theorem.

So for this case we need to satisfy the following condition:

$X_i \sim N(\mu , \sigma), i=1,2,...,n$