You start by using proportions to find the number of liters of solution:
180 g of glucose / 1 liter of solution = 18 g of glucose / x liter of solution
=> x = 18 g of glucose * 1 liter of solution / 180 g of glucose = 0.1 liter of solution.
If you assume that the 18 grams of glucose does not apport volume to the solution but that the volume of the solution is the same volumen of water added (which is the best assumption you can do given that you do not know the how much the 18 g of glucose affect the volume of the solution) then you should add 0.1 liter of water.
Answer: 0.1 liter of water.
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The answer should be <span>C. nuclear reaction.</span>
When a 0. 1 m aqueous solution of hydrocyanic acid, HCN, reaches equilibrium, the ka for hydrocyanic acid is 3.969 x 10⁻¹⁰.
<h3>What is ka value?</h3>
It's the value of equilibrium constant for the dissociation of ions into a solution. The more the Ka value the more will be dissociation.
Ka = [H₃O⁺]² / [HCN] [H₃O⁺]
The pH is 5.20
-log [H₃O⁺] = 5.20
Putting antitlog both side.
The value will be 6.30 x 10⁻⁶
Ka = (6.30 x 10⁻⁶)² / 0.1 - 6.30 x 10⁻⁶
0.1 - 6.30 x 10⁻⁶ = 0.1
Ka = 3.969 x 10⁻¹⁰
Thus, the Ka value for hydrocyanic acid is 3.969 x 10⁻¹⁰.
To learn more about ka value, refer to the link:
brainly.com/question/2796803
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