5q ≥ 8q - 3/2
<em><u>Add 3/2 to both sides.</u></em>
3/2 + 5q ≥ 8q
<em><u>Subtract 5q from both sides.</u></em>
3/2 ≥ 3q
<em><u>Multiply both sides by 2.</u></em>
3 ≥ 6q
<em><u>Divide both sides by 6.</u></em>
0.5 ≥ q.
The value of q is less than or equal to 0.5.
Answer:
-1
Step-by-step explanation:
can be soled by substitution remember BEDMAS
can also be written like this
((-2)-2*(-0.5))^3
116 if you add 72 plus 43
False. If x=-3 and y=-6 and you substitute them into the equation they do not add up
5x+3y=58
5x-3y=22
(3y gets cancelled bc 3y-3y=0, then add 5x with 5x, so you're left with)
10x=80, (divide both sides by 10)
x=8
Now we look for y. So choose one formula from the two (let's say 5x + 3y=58)
Substitute x for 8 so it will look like---- 5(8)+3y=58
Multiply 5*8--- so you get -- 40+3y=58
Subtract 40 from both sides and you're left with 3y=18
divide both sides by 3
you get y=6
In conclusion, x=8 and y=6 hence, (8,6)
