(E) ionic aluminum fluoride (AlF3)
HELPPPPPPPPPPPPPPPPPPPPPPP HELPPPPPPPPPPPPPPPPPPPPPPP
100000000000000 I think):
K₃PO₄ → 3K⁺ + PO₄³⁻
PO₄³⁻ + H₂O ⇄ HPO₄²⁻ + OH⁻
HPO₄²⁻ + H₂O ⇄ H₂PO₄⁻ + OH⁻
H₂PO₄⁻ + H₂O ⇄ H₃PO₄ + OH⁻
K⁺, PO₄³⁻, HPO₄²⁻, H₂PO₄⁻, OH⁻
Answer:
for the given reaction is -2486.3 kJ
Explanation:
The given equation can be written as a combination of the following equation:
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