See explanations below.
Step-by-step explanation:
12. If H(x) represent the percent of U.S households with internet use in x years after 1980 then;
a) H(23)=55 means the number of U.S households with internet use in 23 years after 1980 is 55
b)H(4)=k
so if in 23 years H, is 55, find in 1 year
In 1 year H= 55/23=k
c)H(27) ≥ 61 means in 27 years the number of U.S households with Internet use will be greater or equal to 61 households. If you check the results, in 27 years, H is 55/23 * 27 =64.5 ≅65 households which is at most 61 households.
d) H(17) + H(21)=H(29) means the sum of households with internet use in 17 years and 21 years after 1980 equal the number of households with internet use in 29 years.Checking the results;
H(17) = 55/23 *17 =40.65
H(21)=55/23 *21=50.22
H(17)+H(21)=40.65+50.22=90.87≅91 households
H(29)=55/23 * 29 = 69.34≅69 which is False
13.
h(x)=-7x ; h(x)=63 ⇒replacing x in the second function with -7x
-7x=63
x=63/-7
x=-9
14.
t(x)=3x ; t(x)=23
3x=23
x=23/3 = 7.67
14.
m(x) =4x +15 ; m(x)=7
4x+15=7
4x=7-15 -----------collecting like terms
4x=-7
x=-7/4
15.
k(x)=6x-12 ; k(x) =18
6x-12=18
6x=18+12-------collecting like terms
6x=30
x=30/6
x=5
16. q(x) =1/2x -3 , q (x) =-4
1/2 x-3 =-4------------multiply each term by 2
x-6= -8 ----------------collect like terms
x= -8+6
x= -2
17.
j(x)= -4/5 x + 7 ; j(x)= -5
-4/5 x +7 = -5 ---------multiply each term by 5
-4x+35= -25
-4x=-25-35
-4x=-60
4x=60
x=60/4
x= 15
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Functions ; brainly.com/question/2316114
Keywords : Functions
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Hello,
I note (a,b,c) the result of a quarters, b dimes and c pennies:
2 solutions:
106=( 3, 3, 1)=( 1, 8, 1)
106=( 0, 0, 106) but : 100= 0*25+ 0*10+ 100
106=( 0, 1, 96) but : 100= 0*25+ 1*10+ 90
106=( 0, 2, 86) but : 100= 0*25+ 2*10+ 80
106=( 0, 3, 76) but : 100= 0*25+ 3*10+ 70
106=( 0, 4, 66) but : 100= 0*25+ 4*10+ 60
106=( 0, 5, 56) but : 100= 0*25+ 5*10+ 50
106=( 0, 6, 46) but : 100= 0*25+ 6*10+ 40
106=( 0, 7, 36) but : 100= 0*25+ 7*10+ 30
106=( 0, 8, 26) but : 100= 0*25+ 8*10+ 20
106=( 0, 9, 16) but : 100= 0*25+ 9*10+ 10
106=( 0, 10, 6) but : 100= 0*25+ 10*10+ 0
106=( 1, 0, 81) but : 100= 1*25+ 0*10+ 75
106=( 1, 1, 71) but : 100= 1*25+ 1*10+ 65
106=( 1, 2, 61) but : 100= 1*25+ 2*10+ 55
106=( 1, 3, 51) but : 100= 1*25+ 3*10+ 45
106=( 1, 4, 41) but : 100= 1*25+ 4*10+ 35
106=( 1, 5, 31) but : 100= 1*25+ 5*10+ 25
106=( 1, 6, 21) but : 100= 1*25+ 6*10+ 15
106=( 1, 7, 11) but : 100= 1*25+ 7*10+ 5
106=( 1, 8, 1) is good
106=( 2, 0, 56) but : 100= 2*25+ 0*10+ 50
106=( 2, 1, 46) but : 100= 2*25+ 1*10+ 40
106=( 2, 2, 36) but : 100= 2*25+ 2*10+ 30
106=( 2, 3, 26) but : 100= 2*25+ 3*10+ 20
106=( 2, 4, 16) but : 100= 2*25+ 4*10+ 10
106=( 2, 5, 6) but : 100= 2*25+ 5*10+ 0
106=( 3, 0, 31) but : 100= 3*25+ 0*10+ 25
106=( 3, 1, 21) but : 100= 3*25+ 1*10+ 15
106=( 3, 2, 11) but : 100= 3*25+ 2*10+ 5
106=( 3, 3, 1) is good
106=( 4, 0, 6) but : 100= 4*25+ 0*10+ 0